Civil Engineering- Retaining walls Essay Example | Topics and Well Written Essays - 250 words

Civil Engineering- Retaining walls - Essay ExampleThis force translates into second base by multiplying it by the moment distance, M of all(prenominal) section (Craig 166). M is the distance from the toe of the wall to the centre of gravity of each section. Centre of mass acts at of distance from the apex to base or of distance from the base to apex, for angular sections. Centre of mass acts at the centre of section, for rectangular sections.Summation of the individual sections resisting moments gives the overall resisting moment. The force, Pa, acts at a distance H since the effective storm region is triangular. The resulting moment is Pa multiplied by H. the calculate of safety Fsot is the ratio of moment due to resistance to the moment due to net alive(p) thrust. The slide resistance is the ratio of (the reaction force of the wall multiplied by the coefficient of sliding, 0.44) to the driving force offered by the injury to the wall (Craig 189). The reaction of the wall is the summation of the walls section forces, in his solecism 23.3 k.In question 2, the angle is 26o, and c is still zero therefore, the wall exerts a triangular ram distribution region. Given both the active and passive pressure co-efficient, Ka and Kp respectively, calculate Pa and Pp. The passive pressure is due to the resistance of soil to lateral forces. Ka and consequently, Pa are calculated as in line 1 while Kp = (1+ sin )/ (1 - sin ). Pp = Kp H2 2c (Ka) (H) but this reduces to Pp = Ka H2 since c is zero (Craig 166). The factor of safety, Fsot, as in problem one is the ratio of the summation of resistance moment by the wall to moments due to active thrust of the soil. The factor of safety due to sliding limit is the summation of wall sections reaction force multiplied by sliding coefficient, 0.45 divided by the thrust force of the soil to the